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transmittance setting problem

Posted 6 sept. 2012, 19:41 UTC−4 Version 4.2a 4 Replies

Fy Zhang
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Hello,

I have used comsol to simulate transmittance of a structure. And I have used two methodd to calculate transmittance. The first method is integration the input port and output port and then dividing then. But it is not a good method because of there is some reflection existing that would influence the result(although I set PML in the in the input side and output side). And the other method is that I set all the material of the structure to be air and then integrate the input boundary. And then I use this integration value as the input value of my structure. the material of input side is air so I think the latter one is a good method. I have tried many structure and they all work well except one structure I just simulated and found that the transmittance is bigger than 1. I don't know what the problem with my second method. I wonder if it is right.

Thank you.
4 Replies Last Post 7 sept. 2012, 14:00 UTC−4
Alexander Kuznetsov
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Posted: 1 decade ago 6 sept. 2012, 20:06 UTC−4
you can use port boundary conditions. Then transmission coefficient is calculated automatically.
you can use port boundary conditions. Then transmission coefficient is calculated automatically.
Fy Zhang
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Posted: 1 decade ago 6 sept. 2012, 20:46 UTC−4
But is it accurate? I have used the automatic method and find the result is the same as the first method I describe. So maybe the automatic method would not able to take the reflection case into account.
But is it accurate? I have used the automatic method and find the result is the same as the first method I describe. So maybe the automatic method would not able to take the reflection case into account.
Alexander Kuznetsov
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Posted: 1 decade ago 7 sept. 2012, 12:16 UTC−4
Sure it is. Works just fine for plane waves if setup correctly.
Sure it is. Works just fine for plane waves if setup correctly.
Fy Zhang
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Posted: 1 decade ago 7 sept. 2012, 14:00 UTC−4
but my power source is the electric dipole. So is it accurate in this case?
but my power source is the electric dipole. So is it accurate in this case?

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