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smoothing an analytical function
Posted 13 juil. 2011, 11:26 UTC−4 Parameters, Variables, & Functions Version 4.2 2 Replies
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Hello,
I have an analytical function m'=k*(cs-c). k, cs, c are arguments, that's why I can use analytical function, only (not piecewise f.i.). m' gets negative for c>cs. What I need is a function m'=max(k*(cs-c),0) with a smooth transition from k*(cs-c) to 0. k*(cs-c) is a straight falling line. k is a constant, cs is a function of T, and c is a variable to solve for.
Is there anybody who has a good idea?
Thank you very much!
Michael
I have an analytical function m'=k*(cs-c). k, cs, c are arguments, that's why I can use analytical function, only (not piecewise f.i.). m' gets negative for c>cs. What I need is a function m'=max(k*(cs-c),0) with a smooth transition from k*(cs-c) to 0. k*(cs-c) is a straight falling line. k is a constant, cs is a function of T, and c is a variable to solve for.
Is there anybody who has a good idea?
Thank you very much!
Michael
2 Replies Last Post 14 juil. 2011, 10:10 UTC−4
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Posted:
1 decade ago
Michael,
If I understand correctly, I think you can make it work by multiplying your desired function by a step function where the argument of the step function is c-cs. Then, if c < cs, the argument is positive, and the step function should return a value of +1. If c > cs, the step function should return a zero.
Chris
If I understand correctly, I think you can make it work by multiplying your desired function by a step function where the argument of the step function is c-cs. Then, if c < cs, the argument is positive, and the step function should return a value of +1. If c > cs, the step function should return a zero.
Chris
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Posted:
1 decade ago
Hi Chris,
thank you very much! Your tip is quit right and so simple! It works fine!
Michael
thank you very much! Your tip is quit right and so simple! It works fine!
Michael