Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
9 years ago
17 sept. 2015, 14:29 UTC−4
Hi
there are a few ways, but the simplest if your spring is connected to "ground" you can select the boundary where your spring is attached and add a BC of "Spring Foundation" type and give the stiffness in the different directions.
Another way is to use a Boundary Load BC and use an equation for the Force of the type -kx*u, -ky*v ... where kx, ky, ... are the spring constants, and then you can make this spring non linear or linked to another part or whatever ...
--
Good luck
Ivar
Hi
there are a few ways, but the simplest if your spring is connected to "ground" you can select the boundary where your spring is attached and add a BC of "Spring Foundation" type and give the stiffness in the different directions.
Another way is to use a Boundary Load BC and use an equation for the Force of the type -kx*u, -ky*v ... where kx, ky, ... are the spring constants, and then you can make this spring non linear or linked to another part or whatever ...
--
Good luck
Ivar
Please login with a confirmed email address before reporting spam
Posted:
9 years ago
18 sept. 2015, 03:12 UTC−4
Thanks Ivar,
How to get the results in force and free velocity form??
Thanks Ivar,
How to get the results in force and free velocity form??
Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
Please login with a confirmed email address before reporting spam
Posted:
9 years ago
18 sept. 2015, 05:34 UTC−4
Hi
Forces you get via the reaction forces in the post processing (applies four BC boundaries), these variables must be integrated over the area, check the doc
Velocities are calculated as the time derivative of the displacement (u,v,w) internally these are named in 5.1 (solid.u_tX,solid.u_tY,solid.u_tZ) (earlier version ut,vt... but to get them "smoother" you might need to add a level in the Discretization" and use third or higher order discretization and not the default quadratic type). but time derivatives are only defined if you do a time solver (and use small time steps and higher resolutions
--
Good luck
Ivar
Hi
Forces you get via the reaction forces in the post processing (applies four BC boundaries), these variables must be integrated over the area, check the doc
Velocities are calculated as the time derivative of the displacement (u,v,w) internally these are named in 5.1 (solid.u_tX,solid.u_tY,solid.u_tZ) (earlier version ut,vt... but to get them "smoother" you might need to add a level in the Discretization" and use third or higher order discretization and not the default quadratic type). but time derivatives are only defined if you do a time solver (and use small time steps and higher resolutions
--
Good luck
Ivar