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Ionization of air.

Posted 2 mai 2013, 10:47 UTC−4 Low-Frequency Electromagnetics, Modeling Tools & Definitions, Parameters, Variables, & Functions Version 4.3a 4 Replies

Zdeno Zitny
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Hello.

I have a model that comprises a container filled with air.
From the outside there are two coils
number of turns 1e6
supply current is 1e3 A
in the container are two electrodes voltage + - + e7 V
the pressure in the container was 3000 per annum and the temperature 1E7 K.

The device should break down air to the electrons and ions.
But nothing is doing.

Does anyone advise me why?

Thank you.
4 Replies Last Post 6 sept. 2017, 09:11 UTC−4
Edgar J. Kaiser Certified Consultant
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Posted: 1 decade ago 2 mai 2013, 14:58 UTC−4

The AC/DC application module calculates currents in conductors as well as electric and magnetic fields. It doesn't include dielectric breakdown.

Cheers
Edgar

--
Edgar J. Kaiser
www.emphys.com
The AC/DC application module calculates currents in conductors as well as electric and magnetic fields. It doesn't include dielectric breakdown. Cheers Edgar -- Edgar J. Kaiser http://www.emphys.com
Zdeno Zitny
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Posted: 1 decade ago 3 mai 2013, 04:22 UTC−4
Yes I understan .

Thank very much.
Yes I understan . Thank very much.
Zdeno Zitny
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Posted: 1 decade ago 4 mai 2013, 05:11 UTC−4
Hello.

I tried to use my model stationary electric and magnetic fields from RF EMW frequncy domain ..
The results are better than before.

so I want to ask:

if
The AC / DC application module Calculates currents in conductors as well as electric and magnetic fields. It does not include dielectric breakdown.

1.If AC / DC application module I use in another module will be calculated
Breaking through the dielectric?

2.If be applied electric and magnetic fields from another module will be calculated
Breaking through the dielectric?

Thank you very much.
Hello. I tried to use my model stationary electric and magnetic fields from RF EMW frequncy domain .. The results are better than before. so I want to ask: if The AC / DC application module Calculates currents in conductors as well as electric and magnetic fields. It does not include dielectric breakdown. 1.If AC / DC application module I use in another module will be calculated Breaking through the dielectric? 2.If be applied electric and magnetic fields from another module will be calculated Breaking through the dielectric? Thank you very much.
Teodor Diaconu
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Posted: 7 years ago 6 sept. 2017, 09:11 UTC−4
Hello! Have you managed to solve this?
Hello! Have you managed to solve this?

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