Please login with a confirmed email address before reporting spam
Posted:
2 years ago
1 août 2022, 06:33 UTC−4
When you define the chemical reaction, you must give the rate constants in a proper dimension so that Ri's becomes mol/(m^3·s). If they are no properly defined the reaction term appears in yellow color.
Lasse
When you define the chemical reaction, you must give the rate constants in a proper dimension so that Ri's becomes mol/(m^3·s). If they are no properly defined the reaction term appears in yellow color.
Lasse
Please login with a confirmed email address before reporting spam
Posted:
2 years ago
14 sept. 2022, 04:40 UTC−4
Thank you for your response dear Lasse.
I have defind it well. In the equilibrium reaction node I define the equilibrium constant i.e., Keq which has no units.
My question is how COMSOL calculates the Ri term from Keq?
Thank you for your response dear Lasse.
I have defind it well. In the equilibrium reaction node I define the equilibrium constant i.e., Keq which has no units.
My question is how COMSOL calculates the Ri term from Keq?
Please login with a confirmed email address before reporting spam
Posted:
2 years ago
15 sept. 2022, 02:25 UTC−4
I have never suceeded in using an equilibrium reaction, it just does not converge. Instead, I define an arbitrarily high forward rate constant and calculate the backward rate constant with the equilibrium constant. For example like this:
Reaction: A --> B
Ri = kf[A] - kb[B]
Keq = kf/kb ==> kb = kf/Keq.
Because the reaction rate constants are high, the reaction appears an an equilibrium reaction. You may check it by calculating [B]/[A] if it equals to Keq.
I have never suceeded in using an equilibrium reaction, it just does not converge. Instead, I define an arbitrarily high forward rate constant and calculate the backward rate constant with the equilibrium constant. For example like this:
Reaction: A --> B
Ri = kf*[A] - kb*[B]
Keq = kf/kb ==> kb = kf/Keq.
Because the reaction rate constants are high, the reaction appears an an equilibrium reaction. You may check it by calculating [B]/[A] if it equals to Keq.