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2D Cylinderical coordinate system
Posted 3 août 2011, 17:07 UTC−4 Parameters, Variables, & Functions, Studies & Solvers, Structural Mechanics Version 4.0, Version 4.1, Version 4.2 1 Reply
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Hi,
In my 2D cylindrical structural mechanics model, I am going to simulate almost a quarter of a rubber-like (hyperelastic) material tube (please see the attached picture) and stretch it circumferentially to make it a half tube. I have successfully done this in Cartesian coordinate, however, I prefer to do that in cylindrical system too.
In my V4.2 COMSOL, I have defined a cylindrical coordinate system, but I have problem correctly defining the boundary conditions. In the boundary condition menu, first I selected the Cylindrical coordinate system. For boundary # 3, the displacement in r-direction should be “r-R”, where r is the final radius (unknown) and R is initial radius, which is known. Of course I enter “sys2.r – R” as my Cyl. Coord. Sys. is sys2.
When I enter the expression “sys2.r – R”, the program gives me a warning indicating that R is not a defined variable. So I decided to replace R with sqrt(X^2+Y^2). This resolves the error, but the solution does not converge, which I believe may be due to this expression rather than other solution parameters that may improve the convergence. I have two issues:
1- Although I do not get a warning when I use X and Y when using cyl. coord. sys, I hesitate to use sqrt(X^2+Y^2) because I have already selected Cyl. Coord system, while X and Y are defined in Global coord. Sys.
2- I wonder if I need to use sqrt(x^2+y^2) (i.e. use spatial coord sys) instead of sqrt(X^2+Y^2) (reference coord. Sys), because the frame type was selected Spatial when I was defining the cyl. coord sys. If I didn’t select Spatial, the cyl. Coord. Sys. wouldn’t be available in the physics menu. However, I believe that the reference coord system should be used (i.e. R=sqrt(X^2+Y^2) ).
I appreciate if you give me your opinion about the above issues.
Thanks
J.W.
In my 2D cylindrical structural mechanics model, I am going to simulate almost a quarter of a rubber-like (hyperelastic) material tube (please see the attached picture) and stretch it circumferentially to make it a half tube. I have successfully done this in Cartesian coordinate, however, I prefer to do that in cylindrical system too.
In my V4.2 COMSOL, I have defined a cylindrical coordinate system, but I have problem correctly defining the boundary conditions. In the boundary condition menu, first I selected the Cylindrical coordinate system. For boundary # 3, the displacement in r-direction should be “r-R”, where r is the final radius (unknown) and R is initial radius, which is known. Of course I enter “sys2.r – R” as my Cyl. Coord. Sys. is sys2.
When I enter the expression “sys2.r – R”, the program gives me a warning indicating that R is not a defined variable. So I decided to replace R with sqrt(X^2+Y^2). This resolves the error, but the solution does not converge, which I believe may be due to this expression rather than other solution parameters that may improve the convergence. I have two issues:
1- Although I do not get a warning when I use X and Y when using cyl. coord. sys, I hesitate to use sqrt(X^2+Y^2) because I have already selected Cyl. Coord system, while X and Y are defined in Global coord. Sys.
2- I wonder if I need to use sqrt(x^2+y^2) (i.e. use spatial coord sys) instead of sqrt(X^2+Y^2) (reference coord. Sys), because the frame type was selected Spatial when I was defining the cyl. coord sys. If I didn’t select Spatial, the cyl. Coord. Sys. wouldn’t be available in the physics menu. However, I believe that the reference coord system should be used (i.e. R=sqrt(X^2+Y^2) ).
I appreciate if you give me your opinion about the above issues.
Thanks
J.W.
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1 Reply Last Post 14 août 2011, 12:04 UTC−4