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# degrees of freedom in truss interface
Posted 29 juil. 2010, 09:18 UTC−4 1 Reply
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Hi all,
I´m starting to work with matlab + comsol. In order to do some practice, I simulated a simple 2D truss structure (see attached file) and I got surprised by the "degrees of freedom solved for" in COMSOL. As it has only one mesh-element per node and a total of 5 nodes, I was expecting to have 5 nodes * 2 dof / node = 10 dof. But COMSOL is solving for 22 dof's.
Does anyone can help me understand what are these extra dof's?
Thanks in advance,
Andre
I´m starting to work with matlab + comsol. In order to do some practice, I simulated a simple 2D truss structure (see attached file) and I got surprised by the "degrees of freedom solved for" in COMSOL. As it has only one mesh-element per node and a total of 5 nodes, I was expecting to have 5 nodes * 2 dof / node = 10 dof. But COMSOL is solving for 22 dof's.
Does anyone can help me understand what are these extra dof's?
Thanks in advance,
Andre
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1 Reply Last Post 29 juil. 2010, 17:45 UTC−4
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Posted:
1 decade ago
Hi,
I think I figured out this question. By default COMSOL uses quadratic shlag elements and that's why I got more dof than I was expecting.
After reading the folowing post:
www.comsol.co.in/community/forums/general/thread/5351/
I learned how to change the element order to 1 (linear) and by doing so I finally got a total of 10 dof, which allows me to compare the results with my analytical solution.
Thanks,
I think I figured out this question. By default COMSOL uses quadratic shlag elements and that's why I got more dof than I was expecting.
After reading the folowing post:
www.comsol.co.in/community/forums/general/thread/5351/
I learned how to change the element order to 1 (linear) and by doing so I finally got a total of 10 dof, which allows me to compare the results with my analytical solution.
Thanks,