Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
1 decade ago
14 mars 2010, 13:24 UTC−4
Hi
I would expect that the reaction force sign is defined with respect to the surface normal = direction pointing "outwards" of the volume.
Therefore I find the signs rather coherent that way, but I agree it's a convention issue
Do you agree ?
Good luck
Ivar
Hi
I would expect that the reaction force sign is defined with respect to the surface normal = direction pointing "outwards" of the volume.
Therefore I find the signs rather coherent that way, but I agree it's a convention issue
Do you agree ?
Good luck
Ivar
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Posted:
1 decade ago
15 mars 2010, 06:18 UTC−4
Hi Ivar,
of course it is but the problem is that in my case it works only in x and z directions.
It should be that reaction force directed according axes but this rule works only in x and z directions...
in y direction(where my prescribed displacement applied) it works in opposite way...
Thank you in advance,
Alex
Hi Ivar,
of course it is but the problem is that in my case it works only in x and z directions.
It should be that reaction force directed according axes but this rule works only in x and z directions...
in y direction(where my prescribed displacement applied) it works in opposite way...
Thank you in advance,
Alex
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Posted:
1 decade ago
10 août 2010, 17:14 UTC−4
Hi Alex:
I am having a similar issue, I was wondering if you can help me. I am modeling the insertion of a probe into the a cube. The probe I am having in post processing is that using point evaluation on vertices or boundary integration on the probe boundaries, the reaction force is always zero (in the z-direction of insertion).
I am looking for the resistance force that the probe is experiencing during the insertion - this is the reaction force right?
Also, for those points on the surface of the cube that are not part of the geometry, I cannot do point evaluation of any parameters on those points, any idea why?
I am attaching a simple version of this simulation.
Thank you,
Joe
Hi Alex:
I am having a similar issue, I was wondering if you can help me. I am modeling the insertion of a probe into the a cube. The probe I am having in post processing is that using point evaluation on vertices or boundary integration on the probe boundaries, the reaction force is always zero (in the z-direction of insertion).
I am looking for the resistance force that the probe is experiencing during the insertion - this is the reaction force right?
Also, for those points on the surface of the cube that are not part of the geometry, I cannot do point evaluation of any parameters on those points, any idea why?
I am attaching a simple version of this simulation.
Thank you,
Joe
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Posted:
1 decade ago
11 août 2010, 02:26 UTC−4
Hi Ivar:
I am having a similar issue, I was wondering if you can help me. I am modeling the insertion of a probe into the a cube. The probe I am having in post processing is that using point evaluation on vertices or boundary integration on the probe boundaries, the reaction force is always zero (in the z-direction of insertion).
I am looking for the resistance force that the probe is experiencing during the insertion - this is the reaction force right?
Also, for those points on the surface of the cube that are not part of the geometry, I cannot do point evaluation of any parameters on those points, any idea why?
I am attaching a simple version of this simulation.
Thank you,
Joe
Hi Ivar:
I am having a similar issue, I was wondering if you can help me. I am modeling the insertion of a probe into the a cube. The probe I am having in post processing is that using point evaluation on vertices or boundary integration on the probe boundaries, the reaction force is always zero (in the z-direction of insertion).
I am looking for the resistance force that the probe is experiencing during the insertion - this is the reaction force right?
Also, for those points on the surface of the cube that are not part of the geometry, I cannot do point evaluation of any parameters on those points, any idea why?
I am attaching a simple version of this simulation.
Thank you,
Joe