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Spatial volume integration in partial 3D domain from Derived values?

Posted 10 mars 2024, 16:47 UTC−4 Interfacing, Modeling Tools & Definitions, Modeling Workflow 2 Replies

Yukai Qiao
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Hi, guys,

I intend to obtain data using volume integration from Derived Values. The thing is that i only can get the data of whole 3D domain (such as -10mm=<z<=10mm) instead of partion of that (such as middle half -5mm=<z<=5mm). I have read several blogs, with suggestions by using integration coupling components or adding another physical interface. Besides, most of them are based on 2D model and i couldnt find videos or files to learn. Perhaps there exsit some simple or quick ways to do this calculation, has anyone had this experience?

2 Replies Last Post 11 mars 2024, 08:47 UTC−4
Robert Koslover Certified Consultant
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Posted: 8 months ago 10 mars 2024, 17:08 UTC−4
Updated: 8 months ago 10 mars 2024, 17:06 UTC−4

If all you want is to employ simple constraints on x, y, or z during evaluation, then simple Booleans are very easy to apply. Just multiply your integrand by the appropriate Boolean expression. A true expression evaluates to 1 and a false expression evaluates to 0. For example, suppose you want to integrate a quantity f but only where x<7. Then integrate the quantity f*(x<7). You can combine Boolean expressions to create more complicated logical constraints. Look up the available "operators" in the Help system. Use "&&" for the logical and operation and "||" for logical or. For example, (x>3)&&(x<7) will evaluate to one if x is between 3 and 7, but will evaluate to zero otherwise.

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Scientific Applications & Research Associates (SARA) Inc.
www.comsol.com/partners-consultants/certified-consultants/sara
If all you want is to employ simple constraints on *x*, *y*, or *z* during evaluation, then simple Booleans are very easy to apply. Just multiply your integrand by the appropriate Boolean expression. A *true* expression evaluates to 1 and a *false* expression evaluates to 0. For example, suppose you want to integrate a quantity *f* but only where x
Gunnar Andersson COMSOL Employee

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Posted: 8 months ago 11 mars 2024, 08:47 UTC−4

An alternative is to use one or more Filter datasets. This usually gives a more accurate result than multiplying the integrand by a Boolean expression.

An alternative is to use one or more Filter datasets. This usually gives a more accurate result than multiplying the integrand by a Boolean expression.

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