Robert Koslover
Certified Consultant
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Posted:
3 years ago
1 juil. 2021, 14:15 UTC−4
Updated:
3 years ago
1 juil. 2021, 14:18 UTC−4
Do you mean: (1) the effective area of flux that it "encloses" (so to speak) from the perspective of a self-inductance calculation, (2) the surface area of the wire itself (= ) where r=the wire radius and l=the total length of wire, or (3) something else?
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Scientific Applications & Research Associates (SARA) Inc.
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Do you mean: (1) the effective area of flux that it "encloses" (so to speak) from the perspective of a *self-inductance* calculation, (2) the surface area of the wire itself (= 2*pi*r*l) where *r*=the wire radius and *l*=the total length of wire, or (3) something else?