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AC/DC Module, Surface current density, Layer thickness of Nanoparticles on Polymer

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Hello,

I am trying to build a model of nanoparticles in a polymer. The object is to evaluate the Terminal current and surface current density accross the polymer. One example from the blog, "MAxwell-wagner-Permittivity of Blood" was really helpful. However, unlike their model, my model does not have an intermediate layer between the nanoparticle and the matrix. The model is as below image.

[Image]

My questions are as follows -- 1. Do I need to put a contact impedence BC for the surface of the nanoparticles? 2. If yes, what "Surface thickness (Thin layer)" or "Surface impedance" properties should I use? Note: I am only putting nanoparticles (Such as - TiO2) in polymer (such as - PMMA).

The terminal current is almost the same if I use or do not use the Contact impedence condition, but the surface current density is completey different!

Thank you.

Best, Didar



4 Replies Last Post 9 mai 2021, 11:18 UTC−4
Edgar J. Kaiser Certified Consultant

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Posted: 4 years ago 7 mai 2021, 13:24 UTC−4

Didar,

if you aren't considering a contact layer in your model, you probably don't need it. The electrical contact between the domains is established automatically in a Form Union. It is to be expected to change the results if you use it nevertheless.

Cheers Edgar

-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Didar, if you aren't considering a contact layer in your model, you probably don't need it. The electrical contact between the domains is established automatically in a Form Union. It is to be expected to change the results if you use it nevertheless. Cheers Edgar

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Posted: 4 years ago 7 mai 2021, 15:42 UTC−4
Updated: 4 years ago 7 mai 2021, 15:44 UTC−4

Hi Dr. Edgar,

Thank you, that was indeed helpful.

I had another question, related to this. If I extract the "Surface Charge Density" from the results, the unit I see is C/m^3. I do not quite uniderstand, though I have 2D model, how can the unit be m^3?

[Attached Image]

Thank you.

Hi Dr. Edgar, Thank you, that was indeed helpful. I had another question, related to this. If I extract the "Surface Charge Density" from the results, the unit I see is C/m^3. I do not quite uniderstand, though I have 2D model, how can the unit be m^3? [Attached Image] Thank you.


Edgar J. Kaiser Certified Consultant

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Posted: 4 years ago 8 mai 2021, 04:21 UTC−4

The root physics node in 2D has a setting for model length in the 3rd dimension. The volumetric charge density takes this into account.

Cheers Edgar

-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
The root physics node in 2D has a setting for model length in the 3rd dimension. The volumetric charge density takes this into account. Cheers Edgar

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Posted: 4 years ago 9 mai 2021, 11:18 UTC−4

Thank you Dr. Edgar, that was relly helpful.

Thank you Dr. Edgar, that was relly helpful.

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