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Displacement gradient in axisymmetric model

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Hi there!

I am working on Weak Form PDE in an axisymmetric model and I need to implement the displacement gradient. I am facing problems because COMSOL recognizes PHI as an undefined varible, so I cannot take its derivative. In cartesian coordinates, being u and v my displacement field, I would do my gradient as:

ux uy
vx vy

So, how do I implement then?

ur 1/radius*(d(u,phi)-phi)
vr 1/radius*(d(v,phi)+r)

Idiot question, but it's taking me so long... Please help!

2 Replies Last Post 9 sept. 2016, 12:57 UTC−4
Edgar J. Kaiser Certified Consultant

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Posted: 8 years ago 9 sept. 2016, 10:19 UTC−4
Ingrid,

maybe I misunderstand the issue, but in an axisymmetric model nothing depends on phi, so all derivatives regarding phi should be zero, no?

Cheers
Edgar

--
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Ingrid, maybe I misunderstand the issue, but in an axisymmetric model nothing depends on phi, so all derivatives regarding phi should be zero, no? Cheers Edgar -- Edgar J. Kaiser emPhys Physical Technology http://www.emphys.com

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Posted: 8 years ago 9 sept. 2016, 12:57 UTC−4
Edgar, thanks for your prompt reply. I am trying to evaluate stress at the crack tip of a geometry (like a pac-man) and it depends on the radius and the angle. I have prescribed both displacement and pressure.
To implement in axisymmetric, I need to inform the gradient of the displacement field so I can get the infinitesimal strain tensor. My problem is on how to declare this gradient of the displacement.
Thank you once again.
Edgar, thanks for your prompt reply. I am trying to evaluate stress at the crack tip of a geometry (like a pac-man) and it depends on the radius and the angle. I have prescribed both displacement and pressure. To implement in axisymmetric, I need to inform the gradient of the displacement field so I can get the infinitesimal strain tensor. My problem is on how to declare this gradient of the displacement. Thank you once again.

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