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Posted:
1 decade ago
28 oct. 2010, 08:45 UTC−4
Muhammad,
there is no thing as a circular force. If you want to apply a torque M you must find how to define the Force vector F according to the vector equation M = F x r. M, F, r are all vectors.
Regards
Edgar
Muhammad,
there is no thing as a circular force. If you want to apply a torque M you must find how to define the Force vector F according to the vector equation M = F x r. M, F, r are all vectors.
Regards
Edgar
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Posted:
1 decade ago
28 oct. 2010, 08:51 UTC−4
Thanx Edgar,
But can you please elaborate your answer. lets say i have a circular plate of radius r and height h and i want to apply twist of an angle Theta, what should i do ?
Thanx Edgar,
But can you please elaborate your answer. lets say i have a circular plate of radius r and height h and i want to apply twist of an angle Theta, what should i do ?
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Posted:
1 decade ago
28 oct. 2010, 09:41 UTC−4
Muhammad,
you would probably set one face of your disc to the boundary condition fixed and calculate the displacements of the other face according to the twist angle Theta.
Say the axis of your disc points in z direction, then your displacements are:
Rz = 0
Rx and Ry are to be calculated as functions of x, y and Theta for the other face of the disc. You can enter such expressions into the Constraint fields in the prescribed displacement boundary condition.
An example: along the x-axis you have:
Rx = x . sin(Theta)
Ry = x . (1 - cos(Theta))
Now generalize these expressions for the x-y-plane and you are done.
Regards
Edgar
Muhammad,
you would probably set one face of your disc to the boundary condition fixed and calculate the displacements of the other face according to the twist angle Theta.
Say the axis of your disc points in z direction, then your displacements are:
Rz = 0
Rx and Ry are to be calculated as functions of x, y and Theta for the other face of the disc. You can enter such expressions into the Constraint fields in the prescribed displacement boundary condition.
An example: along the x-axis you have:
Rx = x . sin(Theta)
Ry = x . (1 - cos(Theta))
Now generalize these expressions for the x-y-plane and you are done.
Regards
Edgar
Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
1 decade ago
29 oct. 2010, 01:22 UTC−4
Hi
as a good example take the moment load in the 3.5a structural application mode documentation
--
Good luck
Ivar
Hi
as a good example take the moment load in the 3.5a structural application mode documentation
--
Good luck
Ivar
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Posted:
1 decade ago
29 oct. 2010, 08:59 UTC−4
thankyou al
The information was really helpful
thankyou al
The information was really helpful